If `A=[(1,0,2),(2,1,0),(3,2,1)]` then `3A^(-1)=`

The rank of [(1,0,2),(2,1,0),(3,2,1)]

If A=[(0,1,-2),(-1,0,3),(2,-3,0)] then A+A^(T)=

If A[(2,0,3),(1,-1,2),(3,-2,0)] , then (adj A)A=

If A=[(1,2,3),(2,0,-1),(0,2,-2)],B=[(1,0,0),(0,-1,0),(-1,0,2)] then 4A-3B=

[(1,3,-2),(-3,0,-5),(2,5,0)] =A [(1,0,0),(0,1,0),(0,0,1)] then, C_(2) rarr C_(2)-3C_(1) and C_(3) rarr C_(3) +2C_(1) gives... [(1,0,0),(3,-9,11),(-2,1,4)] =A [(-1,3,2),(0,-1,0),(0,0,-1)] [(1,0,0),(-3,-1,-4),(2,-9,11)] =A [(1,-3,2),(0,1,0),(0,0,1)] [(1,0,0),(-3,1,4),(-2,9,-11)] =A [(-1,3,2),(0,-1,0),(0,0,-1)] [(1,0,0),(-3,9,-11),(2,-1,4)] =A [(1,-3,2),(0,1,0),(0,0,1)]

Let a be a 3xx3 matric such that [(1,2,3),(0,2,3),(0,1,1)]=[(0,0,1),(1,0,0),(0,1,0)] , then find A^(-1) .