Given `tan theta + cot phi= alpha and cot theta + tan phi=beta`

If tan theta + tan phi =a , and cot theta + cot phi =b , and theta - phi = alpha ne 0 , then

If tan theta + tan phi = x "and" cot theta + cot phi = y, "prove that " cot ( theta + phi) = 1/x -1/y

Eliminate theta " and " phi tan theta + tan phi = x, cot theta + cot phi = y, theta + phi = alpha

If tan theta+tan phi=a and cot theta+cot phi=b then cot(theta+phi)=

If tan theta = cos2 alpha tan phi, prove that tan (phi - theta) = (tan^(2) alpha sin 2 phi)/(1+ tan^(2) alpha cos 2 phi)

Prove : (tan theta) /(1- cot theta) + (cot theta)/ (1-tan theta) = 1 + tan theta + cot theta

Eliminate theta, phi from sin theta + sin phi = a , cos theta+ cos phi = b and tan theta/2 * tan phi/2 = c.

if tan theta+tan phi=x and cot theta+cot phi=y prove that cot(theta+phi)=(1)/(x)-(1)/(y)

(sin (theta + phi))/( sin theta cos phi) = cot theta tan phi +1.