Mean deviation for n observation `x_(1),x_(2),…..x_(n)` from their mean `bar x` is given by

Mean deviation for n observations x_(1), x_(2),….., x_(n) from their mean bar(x) is given by :

The mean deviation for n observations x_(1),x_(2),.........,x_(n) from their mean X is given by (a)sum_(i=1)^(n)(x_(i)-X)(b)(1)/(n)sum_(i=1)^(n)(x_(i)-X)(c)sum_(i=1)^(n)(x_(i)-X)^(2)(c)(1)/(n)sum_(i=1)^(n)(x_(i)-X)^(2)

The mean deviation for n observations x_(1),x_(2)…….x_(n) from their median M is given by (i) sum_(i=1)^(n)(x_(i)-M) (ii) (1)/(n)sum_(i=1)^(n)|x_(i)-M| (iii) (1)/(n)sum_(i=1)^(n)(x_(i)-M)^(2) (iv) (1)/(n)sum_(i=1)^(n)(x_(i)-M)

Mean deviation for n observation x_1,x_2,……….,x_n from their mean barx is given by …….

The mean deviation for n observations x_1, x_2, ......... , x_n from their mean X is given by (a) sum_(i=1)^n(x_i- X ) (b) 1/nsum_(i=1)^n(x_i- X ) (c) sum_(i=1)^n(x_i- X )^2 (d) 1/nsum_(i=1)^n(x_i- X )^2

The mean deviation for n observations x_1, x_2, ......... , x_n from their mean X is given by (a) sum_(i=1)^n(x_i- X ) (b) 1/nsum_(i=1)^n|x_i- X | (c) sum_(i=1)^n(x_i- X )^2 (d) 1/nsum_(i=1)^n(x_i- X )^2

If the standard deviation of n observation x_(1), x_(2),…….,x_(n) is 5 and for another set of n observation y_(1), y_(2),………., y_(n) is 4, then the standard deviation of n observation x_(1)-y_(1), x_(2)-y_(2),………….,x_(n)-y_(n) is

If the standard deviation of n observation x_(1), x_(2),…….,x_(n) is 5 and for another set of n observation y_(1), y_(2),………., y_(n) is 4, then the standard deviation of n observation x_(1)-y_(1), x_(2)-y_(2),………….,x_(n)-y_(n) is

Given that bar(x) is the mean and sigma^(2) is the variance of n observation x_(1), x_(2), …x_(n). Prove that the mean and sigma^(2) is the variance of n observations ax_(1),ax_(2), ax_(3),….ax_(n) are abar(x) and a^(2)sigma^(2) , respectively, (ane0) .