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Let f:A to B and g:B to C be bijection, ...

Let `f:A to B and g:B to C` be bijection, then `(fog)^(-1)`=

A

`f^(-1)og^(-1)`

B

fog

C

`g^(-1)of^(-1)`

D

gof

Text Solution

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The correct Answer is:
C
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OBJECTIVE RD SHARMA-FUNCTIONS-Exercise
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