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The bisector of the acute angle formed b...

The bisector of the acute angle formed between the lines 4x - 3y + 7 = 0 and 3x - 4y + 14 = 0 has the equation

A

x + y + 3 = 0

B

x - y - 3 = 0

C

x - y + 3 =0

D

3x - y - 7 = 0

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To find the equation of the bisector of the acute angle formed between the lines \(4x - 3y + 7 = 0\) and \(3x - 4y + 14 = 0\), we can follow these steps: ### Step 1: Identify the coefficients From the equations of the lines, we can identify the coefficients: - For the first line \(4x - 3y + 7 = 0\): - \(A_1 = 4\), \(B_1 = -3\), \(C_1 = 7\) - For the second line \(3x - 4y + 14 = 0\): - \(A_2 = 3\), \(B_2 = -4\), \(C_2 = 14\) ### Step 2: Write the equations for the angle bisectors The equations of the angle bisectors can be expressed as: \[ \frac{A_1x + B_1y + C_1}{\sqrt{A_1^2 + B_1^2}} = \pm \frac{A_2x + B_2y + C_2}{\sqrt{A_2^2 + B_2^2}} \] ### Step 3: Calculate the magnitudes of the coefficients Calculate the magnitudes: - For the first line: \[ \sqrt{A_1^2 + B_1^2} = \sqrt{4^2 + (-3)^2} = \sqrt{16 + 9} = \sqrt{25} = 5 \] - For the second line: \[ \sqrt{A_2^2 + B_2^2} = \sqrt{3^2 + (-4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \] ### Step 4: Substitute into the angle bisector equation Substituting into the angle bisector equation gives: \[ \frac{4x - 3y + 7}{5} = \pm \frac{3x - 4y + 14}{5} \] ### Step 5: Simplify the equation This can be simplified by multiplying through by 5: \[ 4x - 3y + 7 = \pm (3x - 4y + 14) \] This leads to two cases: 1. \(4x - 3y + 7 = 3x - 4y + 14\) 2. \(4x - 3y + 7 = -(3x - 4y + 14)\) ### Step 6: Solve the first case For the first case: \[ 4x - 3y + 7 = 3x - 4y + 14 \] Rearranging gives: \[ 4x - 3x + 4y - 3y + 7 - 14 = 0 \] \[ x + y - 7 = 0 \quad \text{or} \quad x + y = 7 \] ### Step 7: Solve the second case For the second case: \[ 4x - 3y + 7 = -3x + 4y - 14 \] Rearranging gives: \[ 4x + 3x - 3y - 4y + 7 + 14 = 0 \] \[ 7x - 7y + 21 = 0 \quad \text{or} \quad x - y + 3 = 0 \quad \text{or} \quad x - y = -3 \] ### Step 8: Conclusion The equations of the angle bisectors are: 1. \(x + y = 7\) 2. \(x - y = -3\) Since we need the acute angle bisector, we can choose one of the equations based on the context of the problem. The final answer is: - The equation of the bisector of the acute angle formed between the lines is \(x + y = 7\).

To find the equation of the bisector of the acute angle formed between the lines \(4x - 3y + 7 = 0\) and \(3x - 4y + 14 = 0\), we can follow these steps: ### Step 1: Identify the coefficients From the equations of the lines, we can identify the coefficients: - For the first line \(4x - 3y + 7 = 0\): - \(A_1 = 4\), \(B_1 = -3\), \(C_1 = 7\) - For the second line \(3x - 4y + 14 = 0\): ...
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