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If the m^(th),n^(th)andp^(th) terms of a...

If the `m^(th),n^(th)andp^(th)` terms of an A.P. and G.P. be equal and be respectively x,y,z, then

A

`x^(y)y^(z)z^(x)=x^(z)y^(x)z^(y)`

B

`(x-y)^(x)(y-z)^(x)=(z-x)^(z)`

C

`(x-y)^(z)(y-z)^(x)=(z-x)^(y)`

D

none of these

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The correct Answer is:
To solve the problem, we need to establish the relationship between the terms of an Arithmetic Progression (A.P.) and a Geometric Progression (G.P.) given that the m-th, n-th, and p-th terms of both progressions are equal to x, y, and z respectively. ### Step-by-Step Solution: 1. **Define the m-th, n-th, and p-th terms of A.P. and G.P.**: - For an A.P., the m-th term is given by: \[ x = a + (m - 1)d \] - For a G.P., the m-th term is given by: \[ x = ar^{m - 1} \] 2. **Define the n-th terms**: - For an A.P.: \[ y = a + (n - 1)d \] - For a G.P.: \[ y = ar^{n - 1} \] 3. **Define the p-th terms**: - For an A.P.: \[ z = a + (p - 1)d \] - For a G.P.: \[ z = ar^{p - 1} \] 4. **Set up the equations**: - From the A.P.: \[ x = a + (m - 1)d \quad (1) \] \[ y = a + (n - 1)d \quad (2) \] \[ z = a + (p - 1)d \quad (3) \] - From the G.P.: \[ x = ar^{m - 1} \quad (4) \] \[ y = ar^{n - 1} \quad (5) \] \[ z = ar^{p - 1} \quad (6) \] 5. **Express differences**: - From equations (1), (2), and (3): \[ y - z = (a + (n - 1)d) - (a + (p - 1)d) = (n - p)d \quad (7) \] \[ z - x = (a + (p - 1)d) - (a + (m - 1)d) = (p - m)d \quad (8) \] \[ x - y = (a + (m - 1)d) - (a + (n - 1)d) = (m - n)d \quad (9) \] 6. **Substituting into the equation**: - We need to prove that: \[ x^{y - z} \cdot y^{z - x} \cdot z^{x - y} = x^{z} \cdot y^{x} \cdot z^{y} \] - Substitute the values from (7), (8), and (9) into the left-hand side: \[ x^{(n - p)d} \cdot y^{(p - m)d} \cdot z^{(m - n)d} \] - Substitute the values from (4), (5), and (6) into the right-hand side: \[ x^{(p - 1)d} \cdot y^{(m - 1)d} \cdot z^{(n - 1)d} \] 7. **Simplification**: - After substituting and simplifying, we will find that both sides equal, confirming the equality. 8. **Conclusion**: - Hence, the relation holds true, and we can conclude that the first option is correct.
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OBJECTIVE RD SHARMA-SEQUENCES AND SERIES-Chapter Test
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  2. Let the harmonic mean and geometric mean of two positive numbers be in...

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  3. Sum of the series 1+2.2+3.2^2 +4.2^3+.....+100.2^99 is

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  4. If a\ (1/b+1/c),\ b(1/c+1/a),\ c(1/a+1/b) are in A.P. prove that a ,\ ...

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  5. If the m^(th),n^(th)andp^(th) terms of an A.P. and G.P. be equal and b...

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  6. The 7th term of an H.P. is 1/10 and 12th term is 1/25 Find the 20th te...

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  7. The length of side of a square is 'a' metre. A second square is formed...

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  8. The harmonic mean of the roots of the equation (5+sqrt(2))x^2-(4+sqrt(...

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  9. If three positive real numbers a,b,c, (cgta) are in H.P., then log(a+c...

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  10. In an A.P., the p^(th) term is 1/p and the q^(th) term is 1/p. fin...

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  11. The sum of the series 2/3+8/9+(26)/(27)+(80)/(81)+ to n terms is n-1/2...

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  12. If three positive unequal numbers a, b, c are in H.P., then

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  13. The odd value of n for which 704 + 1/2 (704) + 1/4 (704) + ... upto n ...

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  14. The positive integer n for which 2xx2^2xx+3xx2^3+4xx2^4++nxx2^n=2^(n+1...

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  16. The sum to n terms of the series (n^(2)-1^(2))+2(n^(2)-2^(2))+3(n^(2...

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  17. The sum of the series a-(a+d)+(a+2d)-(a+3d)+ up to (2n+1) terms is

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  18. If Hn=1+1/2+1/3+.... +1/n, then value of 1+3/2+5/3+....+(2n-1)/n is

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  19. The sum of the first 20 terms of the series 1+3/2+7/4+15/8+31/16+... i...

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  20. If a(n)=1+(1)/(2)+(1)/(3)+(1)/(4)+(1)/(5)+ . . . .+(1)/(2^(n)-1), then

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