Home
Class 11
MATHS
The number of integral values of m for w...

The number of integral values of m for which the equation `(1+m^(2)) x^(2) - 2(1+3m)x+(1+8m) = 0`, has no real roots is

A

1

B

2

C

3

D

infinitely many

Text Solution

AI Generated Solution

The correct Answer is:
To determine the number of integral values of \( m \) for which the quadratic equation \[ (1+m^2)x^2 - 2(1+3m)x + (1+8m) = 0 \] has no real roots, we need to analyze the discriminant of the quadratic equation. A quadratic equation has no real roots if its discriminant is less than zero. ### Step 1: Identify coefficients The coefficients of the quadratic equation are: - \( a = 1 + m^2 \) - \( b = -2(1 + 3m) \) - \( c = 1 + 8m \) ### Step 2: Write the discriminant The discriminant \( D \) of a quadratic equation \( ax^2 + bx + c = 0 \) is given by: \[ D = b^2 - 4ac \] Substituting our coefficients into the discriminant formula, we have: \[ D = [-2(1 + 3m)]^2 - 4(1 + m^2)(1 + 8m) \] ### Step 3: Simplify the discriminant Calculating \( D \): 1. Calculate \( b^2 \): \[ b^2 = 4(1 + 3m)^2 = 4(1 + 6m + 9m^2) = 4 + 24m + 36m^2 \] 2. Calculate \( 4ac \): \[ 4ac = 4(1 + m^2)(1 + 8m) = 4[(1 + m^2) + 8m(1 + m^2)] = 4(1 + m^2 + 8m + 8m^3) \] \[ = 4 + 4m^2 + 32m + 32m^3 \] 3. Now substitute back into the discriminant: \[ D = (4 + 24m + 36m^2) - (4 + 4m^2 + 32m + 32m^3) \] \[ = 4 + 24m + 36m^2 - 4 - 4m^2 - 32m - 32m^3 \] \[ = 36m^2 - 4m^2 + 24m - 32m - 32m^3 \] \[ = -32m^3 + 32m^2 - 8m \] ### Step 4: Set the discriminant less than zero To find when there are no real roots, we set the discriminant less than zero: \[ -32m^3 + 32m^2 - 8m < 0 \] ### Step 5: Factor the inequality Factoring out \(-8m\): \[ -8m(4m^2 - 4m + 1) < 0 \] ### Step 6: Analyze the quadratic factor The quadratic \( 4m^2 - 4m + 1 \) can be analyzed using the discriminant: \[ D = (-4)^2 - 4 \cdot 4 \cdot 1 = 16 - 16 = 0 \] Since the discriminant is zero, \( 4m^2 - 4m + 1 \) has a double root at: \[ m = \frac{4}{2 \cdot 4} = \frac{1}{2} \] ### Step 7: Determine the sign of the quadratic The quadratic \( 4m^2 - 4m + 1 \) is always positive (it opens upwards and has a double root). Therefore, the sign of the expression \(-8m(4m^2 - 4m + 1)\) depends solely on \( -8m \). ### Step 8: Solve for \( m \) Thus, we need: \[ -8m < 0 \implies m > 0 \] ### Step 9: Count integral values The integral values of \( m \) that satisfy \( m > 0 \) are \( 1, 2, 3, \ldots \), which are infinitely many. ### Final Answer The number of integral values of \( m \) for which the equation has no real roots is **infinitely many**. ---

To determine the number of integral values of \( m \) for which the quadratic equation \[ (1+m^2)x^2 - 2(1+3m)x + (1+8m) = 0 \] has no real roots, we need to analyze the discriminant of the quadratic equation. A quadratic equation has no real roots if its discriminant is less than zero. ...
Promotional Banner

Similar Questions

Explore conceptually related problems

The number of interal values of m for which the equation (1+m^(2))x^(2)-2(1+3m)x+(1+8m)=0, has no ral roots is

The number of integral values of m for which the quadratic expression (1 + 2m)x^(2) - 2(1 + 3m)x + 4(1 + m), x in R , is always positive is

Absolute sum of integral values of m for which the equation (m^(2)+2m+1)x^(2)-2(m+1)x+(m+1)^(4)-9=0 has rational roots is

Number of integral values of a for which the equation x^(2)-(a+1)x+a-1=0, has integral roots,is equal to -

The number of integral values of 'a' for which the quadratic equation x^(2)+(a+19)x+19a+1=0 has integral roots,are

Find the set of real values of 'm' for which the equation ((x)/(1+x^(2)))^(2)-(m-3)((x)/(1+x^(2)))+m=0 has real roots.

The number of positive integral values of m , m le 16 for which the equation (x^(2) +x+1) ^(2) - (m-3)(x^(2) +x+1) +m=0, has 4 distinct real root is:

The number of integral values of m, for which the root of x^(2)-2mx+m^(2)-1=0 will lie between -2 and 4