Home
Class 11
MATHS
The equation (cosp - 1) x^2 +cosp x + si...

The equation `(cosp - 1) x^2 +cosp x + sinp = 0` where x is a variable, has real roots. then the interval of p may be any one of the following :

A

`(0, 2 pi)`

B

`(- pi, 0)`

C

`(-(pi)/(2), (pi)/(2))`

D

`(0, pi)`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

The equation (cos p-1)x^(2)+cos px+sin p=0 where x is a variable,has real roots.then the interval of p may be any one of the following:

The equation (cos p-1) x^(2) + cos p*x + sin p = 0 where x is a variable, has real roots. Then the interval of possible values of p is

The equation (cos p-1)x^(2)+(cos p)x+sin p=0 in the variable x has real roots.The p can take any value in the interval (a) ( 0,2 pi)( b) (-pi,0) (c) (-(pi)/(2),(pi)/(2))( d )(0,pi)

The equation sinx+x cos x=0 has atleast one root in the interval.

The roots of the equation (p - 2)x^2 + 2(p - 2)x+ 2 =0 are not real when-

If the roots of the given equation (cos p-1)x^(2)+(cos p)x+sin p=0 are real if

If the quadratic equation 4 x^ 2 - (p-2)x+ 1 = 0 has equal roots, then the value of 'p' are