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If one of the lines given by 6x^2- xy +4...

If one of the lines given by `6x^2- xy +4cy^2=0` is `3x +4y=0`, then `c=`

A

`-3`

B

`-1`

C

3

D

1

Text Solution

Verified by Experts

The correct Answer is:
A
It is given that `3x+4y=0` i.e. `y=-(3)/(4)x` is one of the lines given by `6x^(2)-xy+4cy^(2)=0`. Therefore, `y=-(3)/(4)x` satisfies it.
`therefore" "6x^(2)+(3)/(4)x^(2)+4xx(9)/(16)x^(2)=0 rArr(27)/(4)+(9c)/(4)=0rArrc=-3`
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