`In `DeltaABC` , ltB=90^(@),tan A=( 3)/(4)`and length of BC =180 m, ten find the length of hypotenuse of `DeltaABC`.

Find the length of AB for the given DeltaABC .

In DeltaABC , /_B=90^(@) . D is the midpoint of hypotenuse AC . If BD=4.5cm , then find the length of hypotenuse AC .

In a DeltaABC , if B=90^(@) , then tan^(2).(A)/(2) =

In a DeltaABC , if B=90^(@) , then tan^(2).(A)/(2) =

In a DeltaABC , if DE is parallel to BC, (AD)/(DB)=(3)/(4) and AC = 15 cm, then find the length AE.

Given below are the lengths of the legs of right DeltaABC . In each case find the length of hypotenuse of DeltaABC : (i) a=32cm, b=60cm (ii) a=28m, b=45m . (iii) a=32cm, b=24cm