Angle between the line vecr=(2hati-hatj+...

Angle between the line `vecr=(2hati-hatj+hatk)+lamda(-hati+hatj+hatk)` and the plane `vecr.(3hati+2hatj-hatk)=4` is

A

`cos^(-1)(2/(sqrt(42)))`

B

`cos^(-1)((-2)/(sqrt(42)))`

C

`sin^(-1)(2/(sqrt(42)))`

D

`sin^(-1)((-2)/(sqrt(42)))`

Text Solution

Verified by Experts

The correct Answer is:

D

NA

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