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The orthogonal trajectories of the circl...

The orthogonal trajectories of the circle `x^(2)+y^(2)-ay=0`, (where a is a parameter), is

A

`x^(2)+y^(2)-ay=0`

B

`x^(2)+y^(2)=Cx`

C

`x^(2)+y^(2)=C`

D

`x^(2)+y^(2)=C(x+y)`

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To find the orthogonal trajectories of the circle given by the equation \( x^2 + y^2 - ay = 0 \), we will follow these steps: ### Step 1: Rewrite the Circle Equation The equation of the circle can be rewritten as: \[ x^2 + (y - \frac{a}{2})^2 = \frac{a^2}{4} \] This shows that the circle is centered at \( (0, \frac{a}{2}) \) with a radius of \( \frac{a}{2} \). ### Step 2: Differentiate the Circle Equation We differentiate the equation \( x^2 + y^2 - ay = 0 \) with respect to \( x \): \[ \frac{d}{dx}(x^2) + \frac{d}{dx}(y^2) - a\frac{dy}{dx} = 0 \] This gives us: \[ 2x + 2y\frac{dy}{dx} - a\frac{dy}{dx} = 0 \] ### Step 3: Solve for \(\frac{dy}{dx}\) Rearranging the equation, we have: \[ 2y\frac{dy}{dx} - a\frac{dy}{dx} = -2x \] Factoring out \(\frac{dy}{dx}\): \[ \frac{dy}{dx}(2y - a) = -2x \] Thus, \[ \frac{dy}{dx} = \frac{-2x}{2y - a} \] ### Step 4: Find the Slope of Orthogonal Trajectories The slope of the orthogonal trajectories is the negative reciprocal of \(\frac{dy}{dx}\): \[ \frac{dy}{dx}_{\text{orthogonal}} = -\frac{1}{\frac{dy}{dx}} = \frac{2y - a}{2x} \] ### Step 5: Set Up the Differential Equation We can set up the differential equation for the orthogonal trajectories: \[ \frac{dy}{dx} = \frac{2y - a}{2x} \] ### Step 6: Separate Variables Rearranging gives: \[ (2y - a) dy = 2x dx \] ### Step 7: Integrate Both Sides Integrating both sides: \[ \int (2y - a) dy = \int 2x dx \] This results in: \[ y^2 - ay = x^2 + C \] where \( C \) is the constant of integration. ### Step 8: Final Form of the Orthogonal Trajectories Rearranging gives us the equation of the orthogonal trajectories: \[ y^2 - ay - x^2 = C \] ### Summary of Steps: 1. Rewrite the circle equation. 2. Differentiate the equation. 3. Solve for \(\frac{dy}{dx}\). 4. Find the slope of orthogonal trajectories. 5. Set up the differential equation. 6. Separate variables. 7. Integrate both sides. 8. Rearrange to get the final form.

To find the orthogonal trajectories of the circle given by the equation \( x^2 + y^2 - ay = 0 \), we will follow these steps: ### Step 1: Rewrite the Circle Equation The equation of the circle can be rewritten as: \[ x^2 + (y - \frac{a}{2})^2 = \frac{a^2}{4} \] This shows that the circle is centered at \( (0, \frac{a}{2}) \) with a radius of \( \frac{a}{2} \). ...
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