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Two parallel chords of a circle, which a...

Two parallel chords of a circle, which are on the same side of centre,subtend angles of `72^@ and 144^@` respetively at the centre Prove that the perpendicular distance between the chords is half the radius of the circle.

A

6

B

4

C

3

D

2

Text Solution

Verified by Experts

The correct Answer is:
A
Required distance = LM
`=OL-OM`
` =12cos 36^(@)-12cos72^(@)`
`=12(cos36^(@)-sin18^(@))`
`=12((sqrt5+1)/(4)-(sqrt5-1)/(4))=6` units.
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