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If x/acosalpha+y/bsinalpha=1, x/acosbeta...

If `x/acosalpha+y/bsinalpha=1, x/acosbeta+y/bsinbeta=1 and (cos alpha cos beta)/a^2+(sin alpha sin beta)/b^2=0,` then

A

`tanalphatanbeta=(b^(2)(x^(2)-a^(2)))/(a^(2)(y^(2)-b^(2)))andx^(2)+y^(2)=a^(2)-b^(2)`

B

`tanalphatanbeta=(a^(2))/(b^(2))`

C

`x^(2)+y^(2)=a^(2)-b^(2)`

D

none of these

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The correct Answer is:
A
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