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2tan^2 alpha tan^2 betatan^2gamma+tan^2 ...

`2tan^2 alpha tan^2 betatan^2gamma+tan^2 alpha tan^2beta+tan^2 betatan^2gamma+tan^2gamma tan^2 alpha=1` find the value of `sin^2 alpha+sin^2 beta +sin^2 gamma`

A

0

B

`-1`

C

1

D

`+-1`

Text Solution

Verified by Experts

The correct Answer is:
C
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OBJECTIVE RD SHARMA-TRIGONOMETRIC RATIOS AND IDENTITIES-Exercise
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