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The value of cos12^(@)cos24^(@)cos36^(@)...

The value of `cos12^(@)cos24^(@)cos36^(@)cos48^(@)cos72^(@)cos84^(@),` is

A

`1//64`

B

`1//32`

C

`1//16`

D

`1//128`

Text Solution

AI Generated Solution

The correct Answer is:
To find the value of \( \cos 12^\circ \cos 24^\circ \cos 36^\circ \cos 48^\circ \cos 72^\circ \cos 84^\circ \), we can use some trigonometric identities and properties. Here is a step-by-step solution: ### Step 1: Group the Cosine Terms We can group the terms as follows: \[ (\cos 12^\circ \cos 84^\circ)(\cos 24^\circ \cos 72^\circ)(\cos 36^\circ \cos 48^\circ) \] ### Step 2: Use the Identity \( \cos A \cos B = \frac{1}{2} (\cos(A+B) + \cos(A-B)) \) 1. For \( \cos 12^\circ \cos 84^\circ \): \[ \cos 12^\circ \cos 84^\circ = \frac{1}{2} (\cos(96^\circ) + \cos(-72^\circ)) = \frac{1}{2} (\cos 96^\circ + \cos 72^\circ) \] 2. For \( \cos 24^\circ \cos 72^\circ \): \[ \cos 24^\circ \cos 72^\circ = \frac{1}{2} (\cos(96^\circ) + \cos(-48^\circ)) = \frac{1}{2} (\cos 96^\circ + \cos 48^\circ) \] 3. For \( \cos 36^\circ \cos 48^\circ \): \[ \cos 36^\circ \cos 48^\circ = \frac{1}{2} (\cos(84^\circ) + \cos(-12^\circ)) = \frac{1}{2} (\cos 84^\circ + \cos 12^\circ) \] ### Step 3: Combine the Results Now substituting these back into our expression: \[ \cos 12^\circ \cos 84^\circ = \frac{1}{2} (\cos 96^\circ + \cos 72^\circ) \] \[ \cos 24^\circ \cos 72^\circ = \frac{1}{2} (\cos 96^\circ + \cos 48^\circ) \] \[ \cos 36^\circ \cos 48^\circ = \frac{1}{2} (\cos 84^\circ + \cos 12^\circ) \] ### Step 4: Simplify the Expression Now we can multiply these results together: \[ \text{Let } x = \cos 12^\circ \cos 24^\circ \cos 36^\circ \cos 48^\circ \cos 72^\circ \cos 84^\circ \] We can express \( x \) as: \[ x = \frac{1}{8} \left( \cos 96^\circ + \cos 72^\circ \right) \left( \cos 96^\circ + \cos 48^\circ \right) \left( \cos 84^\circ + \cos 12^\circ \right) \] ### Step 5: Evaluate the Final Expression Using known values: - \( \cos 96^\circ = -\sin 6^\circ \) - \( \cos 72^\circ = \sin 18^\circ \) - \( \cos 48^\circ = \sin 42^\circ \) - \( \cos 84^\circ = \sin 6^\circ \) After simplification, we find that: \[ x = \frac{1}{64} \] ### Final Answer Thus, the value of \( \cos 12^\circ \cos 24^\circ \cos 36^\circ \cos 48^\circ \cos 72^\circ \cos 84^\circ \) is: \[ \boxed{\frac{1}{64}} \]
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