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If cosA+cosB+cosC=0, then cos3A+cos3B+c...

If `cosA+cosB+cosC=0, then cos3A+cos3B+cos3C` is equal to

A

`cosA cosBcosC`

B

`12cosAcosBcosC`

C

0

D

`8cos^(2)Acos^(3)Bcos^(3)C`

Text Solution

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The correct Answer is:
B
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