If `x=a (theta-sin theta) and y=a(1-cos theta)`, find `(d^(2)y)/(dx^(2))` at `theta=pi.`

If x=a(theta+sintheta) and y=a(1-cos theta) , then find (d^(2)y)/(dx^(2)) at theta=(pi)/(2) .

If x=a(theta-sin theta),y=a(1+cos theta),quad find (d^(2)y)/(dx^(2))

If x=a(theta-sin theta),y=a(1+cos theta) find (d^(2)y)/(dx^(2))

If x=a(theta+sin theta) and y=a(1-costheta) , find (d^2y)/(dx^2)"at"theta=pi/2

Find (d^2y)/(dx^2) in the following If x = a (theta + sin theta) , y = a(1 - cos theta) , find (d^2y)/(dx^2) at theta = pi/2

If x=a(theta-sin theta) and,y=a(1+cos theta) find (dy)/(dx) at theta=(pi)/(3)

If x=a(2 theta-sin2 theta) and y=a(1-cos2 theta) find (dy)/(dx) when theta=(pi)/(3)

If x =a ( theta + sin theta), y =a (1 - cos thea) then (d ^(2) y)/(dx ^(2)) at theta = (pi)/(4) is