The `K_(c)` for `H_(2(g)) + I_(2(g))hArr2HI_(g)` is 64. If the volume of the container is reduced to one-half of its original volume, the value of the equilibrium constant will be

The equilibrium constant of the reaction, H_(2)(g)+I_(2)(g)hArr 2HI(g) is 64. If the volume of the container is reduced to half of its original volume, the value of equilibrium constant will be :

The equilbrium constant of the reaction H_(2)(g)+I_(2)(g)hArr 2HI(g) is 50. If the volume of the container is reduced to half of its original value, the value of equilibrium constant will be

The equilbrium constant of the reaction H_(2)(g)+I_(2)(g)hArr 2HI(g) is 50. If the volume of the container is reduced to half of its original value, the value of equilibrium constant will be

The equilibrium constant of the reaction, H_(2)+I_(2)hArr 2HI is 50. If the volume of the container is reduced to half of its original value, the value of equilibrium constant will be

The equilibrium constant (K_(p)) for the reaction, PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g)) is 16 . If the volume of the container is reduced to half of its original volume, the value of K_(p) for the reaction at the same temperature will be:

The equilibrium constant (K_(p)) for the reaction, PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g)) is 16 . If the volume of the container is reduced to half of its original volume, the value of K_(p) for the reaction at the same temperature will be:

For reaction : H_(2)(h)+I_(2)(g) hArr 2HI(g) at certain temperature, the value of equilibrium constant is 50 . If the volume of the vessel is reduced to half of its original volume, the value of new equilibrium constant will be

For reaction : H_(2)(h)+I_(2)(g) hArr 2HI(g) at certain temperature, the value of equilibrium constant is 50 . If the volume of the vessel is reduced to half of its original volume, the value of new equilibrium constant will be