If `a=x/(y-z),b=y/(z-x),c=z/(x-y)` , wherex, y, z not all zero (non-zero solution)then `ab + bc + ca` is equal to :-

Given a = x/(y - z), b = y/(z - x) and c = z/(x - y) , where x,y and z are not all zero, Then the value of ab + bc + ca a)0 b)1 c)-1 d)None of these

Given a=x/(y-z),b=y/(z-x), and c=z/(x-y), where x,y,z and are not all zero,then the value of ab+bc+ca is 0 b.1 c.-1 none of these

Given a=x//(y-z), b=y//(z-x), and c=z//(x-y),w h e r e .x , y and z are not all zero, then the value of a b+b c+c a is a. 0 b. 1 c. -1"" d. none of these

Given a=x//(y-z), b=y//(z-x), and c=z//(x-y),w h e r e .x , y and z are not all zero, then the value of a b+b c+c a is a. 0 b. 1 c. -1"" d. none of these

Eliminate x,y,z from a=x/y-z, b=y/z-x, c=z/x-y

If a,b and c are non-zero real numbers and if the equation (a-1)x=y+z,(b-1)y=z+x, (c-1)z=x+y has a non-trival solution then ab+bc+ca equals to

If a,b and c are non-zero real numbers and if the equation (a-1)x=y+z,(b-1)y=z+x, (c-1)z=x+y has a non-trival solution then ab+bc+ca equals to