For an alpha particle , accelerated through a potential difference V , wavelength (in ` Å` ) of the associated matter wave is

An alpha - particle is accelerated through a potential difference of 100 V. Its de-Broglie's wavelength is

An alpha - particle is accelerated through a potential difference of 100 V. Its de-Broglie's wavelength is

A proton and an alpha particle are accelerated through the same potential difference. The ratio of the wavelengths associated with the proton to that associated with the alpha particle is

An alpha partaicle is accelerated through a potential difference of 10^4 V . The gain in K.E. of the alpha particle is .

An electron is accelerated through a potential difference of 150 V. Find the wavelength associated with it ?

A proton and an alpha particle are accelerated through the same potential difference V. The ratio of their de Broglie wavelengths is

A proton and and alpha - particle are accelerated through a potential difference of 100 V . The ratio of the wavelength with the proton to that associated to that associated with an alpha - particle is

A proton and an alpha -particle are accelerated through the same potential difference. The ratio of de-Broglie wavelength of proton to the de-Broglie wavelength of alpha particle will be