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When one mole CrCl3 .6H2O is treated wit...

When one mole `CrCl_3 .6H_2O` is treated with excess of `AgNo_3`, 3 mole of AgCl is obtained. The formula of complex is

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When 1 mol CrCl_3 .6H_2O is treated with excess of AgNO_3 , 3 3 mol of AgCl are obtained. The formula of the complex is:

When 1 mol CrCl_(3).6H_(2)O is treated with excess of AgNO_(3) , 3 mol of AgCl are obtained. The formula of the coplex is

When 1 mol CrCl_(3).6H_(2)O is treated with excess of AgNO_(3) , 3 mol of AgCl are obtained. The formula of the coplex is

When 1 mol CrCl_(3).6H_(2)O is treated with excess of AgNO_(3) , 3 mol of AgCl are obtained. The formula of the coplex is

When 1 mole CrCl_(3).6H_(2)O is treated with excess of AgNO_(3), 3 mol AgCl are obtained. Formula of the complex :