An AC voltage of `V=220sqrt2 sin (100pit+(pi)/(2))V` is applied across a DC votlmeter, its reading will be

An AC voltage of V=220sqrt2 sin (100 pit-pi/2) is applied across a DC voltameter its reading will be:

An AC voltage of V=220sqrt2 sin (100 pit-pi/2) is applied across a DC voltameter its reading will be:

An alternating voltage E = 200sqrt(2) sin (100 t)V is applied to a 2 mu F capacitor through an A.C. ammeter. The reading of the ammeter is

An alternating voltage given as, V=100sqrt(2)sin100t V is applied to a capacitor of 1muF . The current reading of the ammeter will be equal to ................ mA.

An alternating voltage given as, V=100sqrt(2)sin100t V is applied to a capacitor of 1muF . The current reading of the ammeter will be equal to ................ mA.

The equation of an alternating voltage is V =100sqrt2 sin 100pit volt. The RMS value of voltage and frequency will be respectively