`|x-2|<=|x+4|`

Solve the following (i) | x-2 | = (x-2) (ii) |x+3 |=-x-3 (iii) |x^2-x|=x^2-x (iv) |x^2-x-2|=2 +x-x^2

f(x)={(a|x^(2)-x-2|)/(2+x-x^(2)),x<2 and b,x=2 and (x-[x])/(x-2),x is continuous at x=2 and [] is GLF.then valueof a and b are

Solve: |[x^2-1, x^2+2x+1, 2x^2+3x+1], [2x^2+x-1, 2x^2+5x-3, 2x^2+4x-3], [6x^2-x-2, 6x^2-7x+2, 12x^2-5x-2]|=0.

Solve: |x^2-1x^2+2x+1 2x^2+3x+1 2x^2+x-1 2x^2+5x-3 2x^2+4x-3 6x^2-x-2 6x^2-7x+2 12 x^2-5x-2|=0.

Solve: |[x^2-1, x^2+2x+1, 2x^2+3x+1], [2x^2+x-1, 2x^2+5x-3, 2x^2+4x-3], [6x^2-x-2, 6x^2-7x+2, 12x^2-5x-2]|=0.

Solve: ,x^(2)-1,x^(2)+2x+1,2x^(2)+3x+12x^(2)+x-1,2x^(2)+5x-3,2x^(2)+4x-36x^(2)-x-2,6x^(2)-7x+2,12x^(2)-5x-2]|=0

Evaluate: lim_(x->2)(x^2-x-2)/(x^2-2x-"sin"(x-2))

Evaluate: lim_(x->2)(x^2-x-2)/(x^2-2x-"sin"(x-2))