Let A(1, 1, 1), B(3, 7, 4) and C (-1, 3, 0) be three
points in a plane.
Area of the triangle ABC is (in sq. units)

Let A(1, 1, 1), B(3, 7, 4) and C (-1, 3, 0) be three points in a plane. The perpendicular distance from C to AB is

Let A(1, 1, 1), B(3, 7, 4) and C (-1, 3, 0) be three points in a plane. The perpendicular distance from C to AB is

Let A(1, 1, 1), B(3, 7, 4) and C (-1, 3, 0) be three points in a plane. The co-ordinates of the foot of perpendicular drawn from point C to the line segment AB is

Let A(1, 1, 1), B(3, 7, 4) and C (-1, 3, 0) be three points in a plane. The co-ordinates of the foot of perpendicular drawn from point C to the line segment AB is

Let A(2,3,4),B(4,3,2) and C(5,2,-1) be three points Find the area of the triangle ABC.

In Fig. 3, the area of triangle ABC (in sq. units) is :

In Fig.3, the area of triangle ABC( in sq.units ) is :

Let A(a, 0), B(b, 2b +1) and C(0, b), b ne 0, |b| ne 1, be points such that the area of triangle ABC is 1 sq. unit, then the sum of all possible values of a is :

Let A(1,1,1),B(2,3,5)a n dC(-1,0,2) be three points, then equation of a plane parallel to the plane A B C which is at distance 2units is

Let A(1,1,1),B(2,3,5)a n dC(-1,0,2) be three points, then equation of a plane parallel to the plane A B C which is at distance 2units is