D is a point on the side BC of a triangle ABC such that `angleADC=angleBAC` . Show `CA^(2)=CB.CD`

D is a point on the side BC of a triangle ABC such that angleADC=angleBAC .Show that CA^2=CB.CD .

D is a point on the side BC of a triangle ABC such that angleADC = angleBAC . Show that CA^2 = CB. CD.

D is a point on the side BC of triangleABC such that angleADC= angleBAC , prove that CA^(2)=CBxxCD .

D is a point on the side BC of a triangle ABC such that /_ADC= /_BAC . Show that CA^(2)= CB*CD .

In the given figure , D is a point on the side BC of Delta ABC such that angle ADC=angle BAC . Prove that CA^(2)=CBxxCD .

D is a point on the side BC of a triangle ABC such that /_A D C=/_B A C . Show that C A^2=C B.C D .

D is a point on the side BC of triangle ABC such that angle ADC = angle BAC . If CA = 12 cm and BC = 16 cm, then the length of CD is :

D is a point on side BC of DeltaABC such that , angleADC=angleBAC . Show that AC^(2)= BCxxDC .

D is a point on the side BC of a angleABC such that angleADC=angleBAC . If CA = 10 cm and BC = 16 cm then the length of CD is:

If D is a Point on the side BC of a Delta ABC such that AD bisects angleBAC . Then