A ball after having fallen from rest under the influence of gravity for 6 s crashes through a horizontal glass plate, thereby losing two-third of its velocity. It then reaches the ground in 2 s, find the height of the plate above the ground.

A stone is dropped from certain height above the ground. After 5 s a ball passes trhough a pane of glass held horizontally and instantaneously loses 20% of its velocity. If the ball takes 2 more seconds to reach the ground the height of the glass above the ground is

An object fallen freely from top of tower reaches at ground in 4s, then find the height of tower. (Take g = 10 ms^(-2) )

A body released from rest to fall freely under gravity reaches the ground in 4 s. Then the height from which it is released is

A ball projected upwards from the foot of a tower. The ball crosses the top of the tower twice after an interval of 6 s and the ball reaches the ground after 12 s . The height of the tower is (g = 10 m//s^2) :

A ball projected upwards from the foot of a tower. The ball crosses the top of the tower twice after an interval of 6 s and the ball reaches the ground after 12 s . The height of the tower is (g = 10 m//s^2) :

A ball projected upwards from the foot of a tower. The ball crosses the top of the tower twice after an interval of 6 s and the ball reaches the ground after 12 s . The height of the tower is (g = 10 m//s^2) :

A body projected up reaches a point A in its path at the end of 4th second and reaches the ground after 5 seconds from the start. The height of A above the ground is (g=10 "m/s"^2)