सिद्ध कीजिए `tan ^(2)A-tan^(2)B=(cos ^(2)B-cos ^(2)A)/(cos ^(2)B cos ^(2)A)=(sin^(2)A-sin^(2)B)/(cos ^(2)A cos ^(2)B)`

Prove the following identities: tan^(2)A-tan^(2)B=(cos^(2)B-cos^(2)A)/(cos^(2)B cos^(2)A)=(sin^(2)A-sin^(2)B)/(cos^(2)A cos^(2)B)(sin A-sin B)/(cos A+cos B)+(cos A-cos B)/(sin A+sin B)=0

sin^(2)A cos^(2)B-cos^(2)A sin^(2)B=sin^(2)A-sin^(2)B

sin^(2) A cos^(2)B + cos ^(2) A sin^(2) B + sin^(2) A sin^(2) B+ cos^(2) A cos^(2) B=

sin ^ (2) A cos ^ (2) B + cos ^ (2) A sin ^ (2) B + sin ^ (2) A sin ^ (2) B + cos ^ (2) A cos ^ (2) B =

cos (A+B).cos(A-B)=cos^(2)A-sin^(2)B

cos (A+B).cos(A-B)=cos^(2)A-sin^(2)B

Prove that :(tan(A+B))/(cot(A-B))=(sin^(2)A-sin^(2)B)/(cos^(2)A-sin^(2)B)

Show that tan^2A-tan^2B=(sin^2A-sin^2B)/(cos^2Acos^2B)

Prove the following identities: tan^2A-tan^2B=(cos^2B-cos^2A)/(cos^2Bcos^2A)=(sin^2A-sin^2B)/(cos^2Acos^2B) (sinA-sinB)/(cosA+cosB)+(cosA-cosB)/(sinA+sinB)=0

Show that: tan(A+B).tan(A-B)=(sin^(2)A-sin^(2)B)/(cos^(2)A-sin^(2)B).