Temperature of two stars are in the ratio 3 : 2 . If wavelenghth for the maximum intensity of the first body is `4000Å` , what is the corresponding wavelenghth of the second body ?

The temperature (approx) of the body omitting wavelength 0.3 mum corresponding to maximum intensity is

The temperature (approx) of the body omitting wavelength 0.3 mum corresponding to maximum intensity is

When the temperature of black body rises, then the wavelength corresponding to the maximum intensity (lamda_(m))

When the temperature of a black body increases, it is observed that the wavelength corresponding to maximum energy changes from 0.26 mu m . The ratio of the emissive powers of the body at the respective temperature is:

Two stars X and Y emit maximum radiations at 4800 Å and 6000 Å respectively. If the temperature of the star Y is 5800 K, then what is the temperature of the star X?

The temperature of one of the two heated black bodies is T_(1) = 2500K . Find the temperature of the other body if the wavelength corresponding to its maximum emissive capacity exceeds by Delta lambda = 0.50mu m the wavelength corresponding to the maximum emissive capacity of the first black body.

When the temperature of a black body increases, it is observed that the wavelength corresponding to maximum energy changes from 0.26mum to 0.13mum . The ratio of the emissive powers of the body at the respective temperatures is

When the temperature of a black body increases, it is observed that the wavelength corresponding to maximum energy changes from 0.26mum to 0.13mum . The ratio of the emissive powers of the body at the respective temperatures is