If `cos2theta=0`, then `|(0,costheta,sin theta),(cos theta, sin theta, 0),(sin theta, 0, cos theta)|^(2)` is equal to…………

If cos2 theta =0 ,determine |(0,cos theta,sin theta),(cos theta ,sin theta,0),(sin theta,0,cos theta)|^(2)

If cos2 theta=0 If det[[0,cos theta,sin thetacos theta,sin theta,0sin theta,o,cos theta]]^(2)

(cos^(2)theta)/(sin theta)-cosec theta+sin theta=0

If A=[(cos theta, sin theta, 0),(-sin theta, cos theta, 0),(0,0,1)] then

The inverse of [(cos theta, -sin theta, 0),(sin theta, cos theta, 0),(0,0,1)] is

If f(theta)=[(cos theta, -sin theta,0),(sin theta, cos theta, 0),(0,0,1)] then {f(theta)^(-1)} is equal to

If f(theta)=|(cos^(2) theta, cos theta sin theta, -sin theta),(cos theta sin theta, sin^(2) theta, cos theta),(sin theta, -cos theta, 0)| then f((pi)/12)=

If sin theta+cos theta=0 and 0