(-i)times(2^(10)times(-(1)/(8)i)^(3)

Simplify: (i) 2^(3)times(-1/2)^(3)times(3/4)^(2)

Simplify ( i ) (((1)/(3))^(-2)-((1)/(2))^(-3)}-:((1)/(4))^(-2)*( ii) ((5)/(8))^(-7)xx((8)/(5))^(-5)

The vector [(i-j+k) times (2i-3j-k)] times [(-3i+j+k) times (2j+k)] is given by

Find the value of ( i^2 + 1 ) times ( i^2 + 2 ) times ( i^2 + 3 ) ------ ( i^2 + n )

i)25xx(t^(-4))/(5^(3)xx10xx t^(-8))ii)3^(-5)xx10^(-5)xx(125)/(5^(-7)xx6^(-5))

Simplify and write the answer in the exponential form.(i) (2^(5)-:2^(8))^(5)xx2^(-5) (ii) (-4)^(-3)xx(5)^(-3)xx(-5)^(-3)( iii) (1)/(8)xx(3)^(-3) (iv) (-3)64xx((5)/(3))^(4)

Simplify: (i) (2 ^(-1) xx 5 ^(-1)) ^(-1) div 4 ^(-1) (ii) (4 ^(-1)+ 8 ^(-1)) div ((2)/(3)) ^(-1)

Simplify: (i) ((2^(5))2xx7^(3))/(8^(3)xx7) (ii) (25xx5^(2)xx t^(8))/(10^(3)xx t^(4))

Evaluate: (i) (-3)/(5)xx(10)/(7)" "(ii) ((-5)/(8))^(-1)" "(iii) (-6)^(-1)

If a=1/sqrt(10)(3i+k)" and "b=1/7(2i+3j-6k) , then the value of (2a-b).[(a times b) times (a+2b)] is