A weight of 1.0 kg is suspended form the lower end of a wire of cross- section ` 10 mm^(2)`. What is the magnitude and direction of stress produced in it ? Take g=`9.8 ms^(-2)`.

A 20kg" load is suspended by a wire of cross section 0.4mm^(2).The stress produced in N/m ' is

A 20kg load is suspended by a wire of cross section 0.4mm^(2) . The stress produced in N//m^(2) is

By how much will a 3.0 m long copper wire elongate if a weight of 10 kg is suspended from the lower end with the upper end keeping fixed? The diameter of the wire is 0.4 mm. Given: Y for copper =10^(11)Nm^(-2) and g=9.8ms^(-2)

Calculate the weight of a body of mass 10 kg in newton . Take g = 9.8 "m s"^(-2) .