Titanium oxide `(TiO_(2))` is heated with excess hydrogen gas to give water and nee oxide `Ti_(x)O_(y)`. If `1.6 gm TiO_(2)` produces `1.44 g Ti_(x)O_(y)`, then select statement (Molar mass of titanium is `48 g//mol`):

H_(2) gas is often used as a reducing gas. In a particular set up 17.4 gm of MnO_(2) on reacting with excess of hydrogen gas gives water and new oxide Mn_(x)O_(y) such that mass of the oxide obtained is 12.6 g. What will be value of y if x is 2. [Mn=55]

H_(2) gas is often used as a reducing gas. In a particular set up 17.4 gm of MnO_(2) on reacting with excess of hydrogen gas given water & new oxide Mn_(x)O_(y) such that mass of the oxide obtained is 12.6. what will be value of y if x is 2.[Mn=55]

The volume strength of g1 M H_(2)O_(2) is : (Molar mass of H_(2)O_(2) = 34 g mol^(-1) )

The volume strength of 0.81 M H_(2)O_(2) is : (Molar mass of H_(2)O_(2) = 34 g mol^(-1) )

1.44 gram if titanium (Ti) reacted with excess of O_(2) and produce x gram of non - stoichiometric compound Ti_(1.44)O . The value of x is :

1. 44 gram if titanium (Ti) reacted with excess of O_(2) and produce x gram of non - stoichiometric compound Ti_(1.44)O . The value of x is :

1, 44 gran if tutanium (Ti) reacted with excess of O_(2) and produce x gram of non - stoichiometric compound Ti_(1.44)O . The value of x is :

The volume strength of 1 M H_(2)O_(2) is : (Molar mass of H_(2)O_(2) = 34 g mol^(-1)

The volume strength of 1 M H_(2)O_(2) is : (Molar mass of H_(2)O_(2) = 34 g mol^(-1)