The equation of a normal to the parabola `y=x^(2)-6x+6` which is perpendicular to the line joining the origin to the vertex of the parabola is

Equation of the normal to the parabola y^(2)=4 x which is perpendicular to x+3 y+1=0

The equation of the tangent to the parabola y^(2)=16x, which is perpendicular to the line y=3x+7 is

Find the equation of the normal to the parabola y^2=4x which is perpendicular to the line 2x+6y+5=0.

Find the equation of the normal to the parabola y^2=4x which is perpendicular to the line 2x+6y+5=0.

Find the equation of the normal to the parabola y^2=4x which is perpendicular to the line 2x+6y+5=0.

Find the equation of the normal to the parabola y^2=4x which is perpendicular to the line 2x+6y+5=0.

Find the equation of the normal to the parabola y^2=4x which is perpendicular to the line 2x+6y+5=0.

(a) Find the slope of the tangent to the cube parabola y = x^(3) at the point x=sqrt(3)/(3) (b) Write the equations of the tangents to the curve y = (1)/(1+x^(2)) at the 1 points of its intersection with the hyperbola y = (1)/(x+1) (c) Write the equation of the normal to the parabola y = x^(2) + 4x + 1 perpendicular to the line joining the origin of coordinates with the vertex of the parabola. (d) At what angle does the curve y = e^(x) intersect the y-axis

The equation of the normal to the parabola y^(2) = 4 x which is perpendicular to x + 3y +1 = 0 is