`x+ 2y + 3z + 1 = 0 ,2x + y - z + 5 = 0 ,3x+ y - 2z = 0 `

Prove that the lines 3x + 2y + z – 5 = 0 = x + y – 2z – 3 and 2x – y – z = 0 = 7x + 10y – 8z – 15 are perpendicular

Solve the system: x + y - 2z = 0, 2x - 3y + z = 0, 3x - 7y + 10z = 0, 6x - 9y + 10z = 0.

The lines x + y + z - 3 = 0 = 2x - y + 5z - 6 and x - y - z + 1 = 0 = 2x + 3y + 7z - k are coplanar then k equals

Solve the following system of equation by matrix method x+2y +3z+1= 0, -2x+y-z +5=0 ,3x +y-2z -3=0

The shortest distance between the lines 2x + y + z - 1 = 0 = 3x + y + 2z - 2 and x = y = z , is

The equation of the line which intersect each of the two lines 2x+y-1 =0 =x-2y+3z and 3x -y+z+2 = 0 = 4x + 5y - 2z-3 = 0 and is parallel to (x)/(1)=(y)/(2)=(z)/(3) is

The equation of the line which intersect each of the two lines 2x+y-1 =0 =x-2y+3z and 3x -y+z+2 = 0 = 4x + 5y - 2z-3 = 0 and is parallel to (x)/(1)=(y)/(2)=(z)/(3) is

If the lines 2x-y+3z + 4 = 0=ax + y-z + 2 and x-3y + z=0 =x + 2y + z +1 are coplannar then the value of a is ...........