`DeltaS_(sur)` for `H_(2)+1//2O_(2) rarr H_(2)O, Delta H = -280 KJ` at 400 K is

DeltaS_("surr") " for " H_(2) + 1//2O_(2) rarr H_(2)O, DeltaH -280 kJ at 400K is

DeltaS_("surr") " for " H_(2) + 1//2O_(2) rarr H_(2)O, DeltaH -280 kJ at 400K is

If S + O_(2) rarr SO_(2), Delta H = -298.2 kJ SO_(2) + (1)/(2) O_(2) rarr SO_(3), Delta H = -98.2 kJ SO_(3) + H_(2)O rarr H_(2)SO_(4), Delta H = -130.2 kJ H_(2) + (1)/(2) O_(2) rarr H_(2)O, Delta H = -287.3 kJ the enthalpy of formation of H_(2)SO_(4) at 298 K will be

If {:(SO_(2)+1/2O_(2) rarr SO_(3),DeltaH = -98.7 kJ),(SO_(3)+H_2O rarr H_(2)SO_(4),DeltaH = -130.2 kJ),(H_(2)+1/2O_(2) rarr H_2O , Delta H = -287.3 kJ),(S + H_2 + 2O_(2) rarr H_2SO_4, DeltaH = -814.4 kJ):} Then enthaply of SO_(2) at 298 K is:

If {:(SO_(2)+1/2O_(2) rarr SO_(3),DeltaH = -98.7 kJ),(SO_(3)+H_2O rarr H_(2)SO_(4),DeltaH = -130.2 kJ),(H_(2)+1/2O_(2) rarr H_2O , Delta H = -287.3 kJ),(S + H_2 + 2O_(2) rarr H_2SO_4, DeltaH = -814.4 kJ):} Then enthaply of SO_(2) at 298 K is:

C_(2)H_(2) + 5/2 O_2(2) rarr 2CO_(2) + H_(2)O , Delta H = -310 kcal C + O_(2) rarr CO_(2) , " "Delta H = -94 kcal H_(2) + 1/2 O_(2) rarr H_(2)O, " " Delta H = -68 kcal On the basis of the above equations, DeltaH_(f) (enthalpy of formation) of C_2H_2 will be :

C_(2)H_(2) + 5/2 O_2(2) rarr 2CO_(2) + H_(2)O , Delta H = -310 kcal C + O_(2) rarr CO_(2) , " "Delta H = -94 kcal H_(2) + 1/2 O_(2) rarr H_(2)O, " " Delta H = -68 kcal On the basis of the above equations, DeltaH_(f) (enthalpy of formation) of C_2H_2 will be :

NaOH_((aq)) + HCl_((aq)) rarr NaCl_((aq)) + H_(2)O, Delta H= -13.6 Kcal. H_(2(g)) + (1)/(2) O_(2(g)) rarr H_(2)O , Delta H = - 68 Kcal. What is hat of formation of OH^(-) ?