`underset(x to -1)"Lt" (x+1)/(2-sqrt(4+x+x^(2)))=`

underset(x to 0)"Lt" (x)/(1-sqrt(1-x))=

underset(x to 1)"Lt" (x-1)/(sqrt(x^(2)+3)-2)=

underset(x to oo)"Lt" 1/x^(2)=

underset(x to 0)"Lt" (x)/(sqrt(x+4)-2)=

underset(x to 0)"Lt" 1/x^(2)=

The arrangement of the following limit values in the ascending order [A=underset(x to 1)"Lt" (x-1)/(sqrt(x^(2)+3)-2)] , [B=underset(x to 0)"Lt"(sqrt(1+x+x^(2))-1)/(x)] , [C=underset(x to 0)"Lt"((1+x)^((3)/(2))-1)/(x)] , [D=underset(x to 4)"Lt"(3-sqrt(5+x))/(x-4)]

underset(x to 1)"Lt" sqrt(1-x)=

underset(x to 2-)"Lt" sqrt(2-x)=

underset(x to 0)"Lt" (2^(x)-1)/((sqrt(1+x)-1))=

underset(x to 1)"Lt" (x^(2)-1)/(|x-1|=