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" 3."2x+3y=2;x-y=(1)/(2)...

" 3."2x+3y=2;x-y=(1)/(2)

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2x+3y=2,x-(y)/(2)=(1)/(2) .

3x+2y=8 2x-3y=1

If ((2x-y)/(x+2y))=(1)/(2), then find the value of ((3x-y)/(3x+y))

Solve:(1)/(2(2x+3y))+(12)/(7(3x-2y))=(1)/(2)(7)/(2x+3y)+(4)/(3x-2y)=2 where 2x+3y!=0 and 3x-2y!=0

Find the products: 2x+3y)(2x-3y)(x-1)(x+1)(x^(2)+1)(x^(4)+1)

" (2) "3x+y=-1,2x-3y=-8

(x + 2) (x + 1) = (x -2) (x -3) (y+3)(y+2)=(y-1)(y-2)

Factorize : (1) (x+y)(2x+3y)-(x+y)(x+1) (2) (x+y)(2a+b)-(3x-2y)(2a+b)