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Let a = (log3 pi)(log2 3)(logpi 2), b = ...

Let `a = (log_3 pi)(log_2 3)(log_pi 2), b = (log 576)/(3 log 2 + log 3)` the base of the logarithm being 10, c=2( sum of the solution of the equation `(3)^(4x) – (3)^(2x+log_3 12) + 27=0`) and `d = 7^(log_7 2 + log_7 3)` then `(a+b+c+d)` simplifies to

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