An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach – 350 m.

Options

A. `1.5h`
B. `1hr 5min`
C. `2hr`
D. `1hr`

Explanation

To solve the problem step by step, we need to determine how long it will take for the elevator to descend from 10 meters above ground level to -350 meters.

### Step 1: Determine the total distance the elevator needs to descend.

The elevator starts at 10 meters above ground level and descends to -350 meters. We can calculate the total distance descended as follows:

\[ \text{Total Distance} = \text{Starting Height} - \text{Final Height} \]
\[ \text{Total Distance} = 10 - (-350) = 10 + 350 = 360 \text{ meters} \]

### Step 2: Identify the rate of descent.

The elevator descends at a rate of 6 meters per minute.

### Step 3: Calculate the time taken to descend the total distance.

We can use the formula for time, which is:

\[ \text{Time} = \frac{\text{Distance}}{\text{Rate}} \]

Substituting the values we have:

\[ \text{Time} = \frac{360 \text{ meters}}{6 \text{ meters/minute}} = 60 \text{ minutes} \]

### Conclusion:

It will take the elevator 60 minutes to reach -350 meters.

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