The velocity v, of a parachute falling vertically satisfies the equation `v(dv)/(dx)=g(1-v^(2)/(k^(2)))`, where g and k are constants. If v and x are both initially zero, find v in terms of x.

The velocity v of a parachute falling vertically satisfies the equation v(dv)/(dx)=g(1-v^2/k^2) , where g and k are positive constants, if both v and x are zero initially, find v in terms of x.

Evaluate int (dv)/(1+2v)

If p=9, v=3 , then find p is terms of v from the equation (dp)/(dv)=v+1/v^2

If p=9, v=3 , then find p is terms of v from the equation (dp)/(dv)=v+1/v^2

The velocity of a particle moving along the xaxis is given by v=v_(0)+lambdax , where v_(0) and lambda are constant. Find the velocity in terms of t.

The velocity of a particle along a straight line increases according to the linear law v=v_(0)+kx , where k is a constant. Then

The velocity of a particle along a straight line increases according to the linear law v=v_(0)+kx , where k is a constant. Then

The solution of (dv)/(dt)+(k)/(m)v=-g is