The displacement of a particle in time t is given by `s=2t^2-3t+1`. The acceleration is

The distance s of a particle in time t is given by s=t^3-6t^2-4t-8 . Its acceleration vanishes at t=

The displacement of a particle at time t is given by s= 2t^(3) -5t^(2)+ 4t-3 . The time when the acceleration is 14ft/ sec^(2) is

If the distance s travelled by a particle in time t is given by s=t^2-2t+5 , then its acceleration is

The displacement of a particle in time 't' is given by S = t^(3) - t^(2) - 8t =18 . The acceleration of the particle when its velocity vanishes is

The displacement s of a particle at time t is is given by s=2 t^3 - 4 t^2 -5t. Then find the velocity at t=2 sec

The displacement s of a particle at time t is is given by s=2 t^3 - 4 t^2 -5t. Then find the time when the acceleration is 14ft/ sec^2

The displacement s of a particle at time t is given by s = t^3 -4 t^2 -5t. Find the velocity and acceleration at t=2 sec

A particle moves along a straight line such that its displacement at any time t is given by s = 3t^(3)+7t^(2)+14t + 5 . The acceleration of the particle at t = 1s is