`(128)^(1//3)~~....`

(128)^(1//7) =

Simplify : (128)^((1)/(7))

Simplify : (128)^((1)/(7))

Simplify : (128)^((1)/(7))

Simplify : (128)^((1)/(7))

Simplify : (128)^((1)/(7))

Solve 32^((x+5)/(x-7))= 1/4 * 128^((x+17)/(x-3)) .

Statement-1: The remainder when (128)^((128)^128 is divided by 7 is 3. because Statement-2: (128)^128 when divided by 3 leaves the remainder 1.

Statement-1: The remainder when (128)^((128)^(128)) is divided by 7 is 3. because Statement-2: (128)^(128) when divided by 3 leaves the remainder 1 .