If `x=acostheta,y=bsintheta" then "(x^(2))/(a^(2))+(y^(2))/(b^(2))=?`

Statement-I : Let A(0,0),B(cosalpha,sinalpha),C(sinalpha-cosalpha) are vertices of a trianlge then the locus of the centroid of triangle is 9x^(2)+9y^(2)=4 Statement-II : The locus of the point (acostheta,bsintheta) is (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 The correct statement is

If x=acostheta and y=bsintheta then b^(2)x^(2)+a^(2)y^(2)= …………. .

If x=acostheta,y=bsintheta," then"(d^(3)y)/(dx^(3)) is equal to

If x=acostheta,y=bsintheta," then"(d^(3)y)/(dx^(3)) is equal to

If x=acostheta , y=bsintheta , show that (d^2y)/(dx^2)=-(b^4)/(a^2y^3) .

If x=acostheta , y=bsintheta then eliminate theta .

If x=acostheta and y=bsintheta , then b^2x^2+a^2y^2= (a) a^2b^2 (b) a b (c) a^4\ b^4 (d) a^2+b^2

If x=acostheta,y=bsintheta, then prove that (d^3y)/(dx^3)=(3b)/(a^3)cos e c^4thetacotthetadot

If x=acostheta,y=bsintheta, then prove that (d^3y)/(dx^3)=(3b)/(a^3)cos e c^4thetacotthetadot

If x=acostheta,y=bsintheta, then prove that (d^3y)/(dx^3)=(3b)/(a^3)cos e c^4thetacotthetadot