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A wire of length L carrying current I i...

A wire of length L carrying current I is bent into a circle of one turn. The field at the center of the coil is B1. A similar wire of length L carrying current I is bent into a square of one turn. The field at its center is B2. Then
(1) `B_(1) gt B_(2)`
(2) `B_(1) = B_(2)`
(3) `(B_(1))/(B_(2))=2`
(4) `B_(1) lt B_(2)`

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