`10 mL` of hydrogen combine with `5mL` of oxygen to yield water. When 200 mL of hydrogen at N.T.P. are passed over heated `CuO`, the latter loses `0.144 g` of its mass. Do these results agree with the law of constant composition ?

10 mL of hydrogen combines with 5 mL of oxygen to yield water. When 200 mL of hydrogen at STP is passed over heated CuO , the CuO loses 0.144 g of its wieght. Do these result correspond to the law of constant composition?

112 mL of hydrogen combines with 56 mL of oxygen of form water. When 224 mL of hydrogen is passes over hand cupric oxide, the cupric oxide loses. 0.160 g of weight. All volumes are measured at STP . Show that the result agrees with the law of constant composition (22.4 L hydrogen and oxygen at STP weigh, respectively, 2g and 32 g )

112 mL of hydrogen combines with 56 mL of oxygen of form water. When 224 mL of hydrogen is passes over hand cupric oxide, the cupric oxide loses. 0.160 g of weight. All volumes are measured at STP . Show that the result agrees with the law of constant composition (22.4 L hydrogen and oxygen at STP weigh, respectively, 2g and 32 g )

112 mL of hydrogen combines with 56 mL of oxygen of form water. When 224 mL of hydrogen is passes over hand cupric oxide, the cupric oxide loses. 0.160 g of weight. All volumes are measured at STP . Show that the result agrees with the law of constant composition (22.4 L hydrogen and oxygen at STP weigh, respectively, 2g and 32 g )

Copper gives two oxides. On heating 1.0 g of each in hydrogen gas, 0.888 g and 0.799 g of the metal are produced. Show that the results agree with the Law of Multiple Proportions.

0.22 g of a hydrogen (i.e., a compound conatining carbon and hydrogen only) on complete combustion with oxygen gave 0.9 g water and 0.44 g carbon dioxide. Show that these results are in accordance with the law of conservation of mass (atomic mass of C = 12, H = 1, O = 16) .

0.4 g hydrogen combines with the 3.2 g oxygen to produce water. Hydrogen sulphide is produced by combination of 0.25 g hydrogen and 4.0g sulphur. 1g of sulphur combines with 1 g of oxygen show that the results are in accordance with the law of reciprocal proportion.