`int_0^sqrt2 [x^2]dx`

int_0^(sqrt(2)) [x^2] dx is equal to (A) 2-sqrt(2) (B) 2+sqrt(2) (C) sqrt(2)-1 (D) sqrt(2)-2

int_0^(sqrt(2)) [x^2] dx is equal to (A) 2-sqrt(2) (B) 2+sqrt(2) (C) sqrt(2)-1 (D) sqrt(2)-2

If [dot]a n d\ {dot} denote respectively the greatest integer and fractional part functional respectively, evaluate the following integral: int_0^(sqrt(2))[x^2]dx

If [dot]a n d\ {dot} denote respectively the greatest integer and fractional part functional respectively, evaluate the following integral: int_0^(sqrt(2))[x^2]dx

int_0^sqrt(2)["x"^2]"dx" is equal to a. 2-sqrt(2) b. 2+sqrt(2) c. sqrt(2)-1 d. -sqrt(2)-2

Evaluate each of the following integral: int_0^2sqrt(4-x^2)dx

Evaluate each of the following integral: int_0^2sqrt(4-x^2)dx

int_(0)^(sqrt(2)) [x^(2)]dx , is

int_(0)^(sqrt(2)) [x^(2)]dx , is

The value of int_(0)^(sqrt(2))[x^(2)]dx is -