If `n=cosalpha/cosbeta`, `m=sinalpha/sinbeta` then `(m^2-n^2)sin^2beta` is

(cosalpha+cosbeta)^2+(sinalpha+sinbeta)^2 =

If cosalpha+cosbeta=0=sinalpha+sinbeta" then "cos2alpha+cos2beta

If cosalpha/cosbeta=m and cosalpha/sinbeta=n then Show that (m^2+n^2) cos^2beta=n^2 .

(cosalpha)/(cosbeta)=n and (sinalpha)/(sinbeta)=m , find (m^(2)-n^(2))sin^(2)beta

If cosalpha+cosbeta=0=sinalpha+sinbeta , then cos2alpha+cos2beta=?

If (cosalpha)/(cosbeta)=m and (cosalpha)/(sinbeta)=n show that (m^2+n^2)cos^2beta=n^2

If cosalpha+cosbeta=0=sinalpha+sinbeta, then prove that cos2alpha+cos2beta=-2cos(alpha+beta) .

If cosalpha+cosbeta+cosgamma=0=sinalpha+sinbeta+singamma then sin(2alpha-beta-gamma)+sin(2beta-gamma-alpha)+sin(2gamma-alpha-beta)=