With two resistances `2 Omega` and `3 Omega` In parallel a third resistance of `4 Omega` is connected in series.Find their equivalent resistance.

Two resistors having resistance 4 Omega and 6 Omega are connected in parallel. Find their equivalent resistance.

Two resistance 60.36 Omega and 30.09 Omega are connected in parallel. The equivalent resistance is

The resistance of each arm of Wheatstone Bridge is 10 Omega . A resistance of 10 Omega is connected in series with the galvanometer then equivalent resistance across battery will be

Two resistances R_(1) = 100 +- 3 Omega and R_(2) = 200 +- 4 Omega are connected in series . Find the equivalent resistance of the series combination.

Two resistances R_(1) = 100 +- 3 Omega and R_(2) = 200 +- 4 Omega are connected in series . Find the equivalent resistance of the series combination.

Two resistances R_(1) = 100 +- 3 Omega and R_(2) = 200 +- 4 Omega are connected in series . Find the equivalent resistance of the series combination.

Two resistance (200 pm 4) Omega and (150 pm 3) Omega are connected in series . What is their equivalent resistance ?

What percent will be the equivalent resistance of two resistances 2 Omega and 3 Omega in their parallel combination with respect to their equivalent resistance in series combination?