If `x^(1//3)+y^(1//3)=z^(1//3)`, then `{(x+y-z)^3+27 x y z}` equals a. `0` b. `-1` c. `1` d. `27`

if x^(1//3)+y^(1//3)-z^(1//3)=0 , then {(x+y-z)^3+27 xyz} is equal to

If x^(1/3)+y^(1/3)=z^(1/3), then {(x+y-z)^(3)+27xyz} equals a.0 b.-1 c. 1d.27

If x^(1/3)+y^(1/3)+z^(1/3)=0 , then prove that (x+y+z)^3=27xyz

If x^(1//3)+ y ^(1//3)+z^(1//3)= 0 " then what is "(x+y+ z)^(3) equal to ?

If x^(1//3) + y^(1//3) + z^(1//3) = 0 , then the value of (x + y + z)^3 is :

If x^((1)/(3))+y^((1)/(3))+z^((1)/(3))=0;x+y+z=

If x^((1)/(3)) + y^((1)/(3)) + z^((1)/(3)) = 0 , then prove that (x + y + z)^(2) = 27 xyz

If x!=y!=za n d|[x,x^2, 1+x^3],[y ,y^2 ,1+y^3],[z, z^2, 1+z^3]|=0, then the value of x y z is a. 1 b. 2 c. -1 d. 2